9y^2-244y+576=0

Solution for 9y^2-244y+576=0 equation:

9y^2-244y+576=0

a = 9; b = -244; c = +576;
Δ = b2-4ac
Δ = -2442-4·9·576
Δ = 38800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{38800}=\sqrt{400*97}=\sqrt{400}*\sqrt{97}=20\sqrt{97}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-244)-20\sqrt{97}}{2*9}=\frac{244-20\sqrt{97}}{18}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-244)+20\sqrt{97}}{2*9}=\frac{244+20\sqrt{97}}{18}
$